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Solana Network的联合创始人Anatoly Yakovenko认为,如果没有2层的标记,那么第1层解决方案就足够了,而这些解决方案没有真正的长期利益。

A co-founder of a popular cryptocurrency took a swipe at Layer-2 cryptos, claiming that these rollups are only redundant and make blockchain scaling more complicated.
流行的加密货币的联合创始人对2层加密货币进行了滑动,声称这些汇总只是多余的,并且使区块链的扩展更加复杂。
Anatoly Yakovenko, co-founder of the Solana (CRYPTO: SOL) network, argued that Layer-1 solutions are sufficient without Layer-2 tokens which do not offer genuine, long-term benefits.
Solana(Crypto:Sol)网络的联合创始人Anatoly Yakovenko认为,如果没有2层的标记,则第1层解决方案就足够了,而这些解决方案不提供真正的长期福利。
Layer-2 Not Needed?
不需要第2层?
Yakovenko said in an X post that Layer-2 cryptocurrencies are unnecessary and only add unnecessary complexity to blockchain scaling.
Yakovenko在X帖子中说,第2层加密货币是不必要的,只为区块链缩放增添了不必要的复杂性。
“There is no reason to build an L2,” Yakovenko said in a post, which is the Solana co-founder’s response to @ripdoteth, who claimed that there is no reason to build a Layer-1.
Yakovenko在一篇文章中说:“没有理由建造L2。
The crypto co-founder argued that Layer-1 solutions, like the Solana network, can already offer efficient, cheap, and secure scaling solutions. Hence, he said that Layer-2 tokens are only providing redundancy.
加密联合创始人认为,像Solana网络一样,第1层解决方案已经可以提供有效,便宜和安全的缩放解决方案。因此,他说,第二层令牌只提供冗余。
There is no reason to build an L2.
没有理由建造L2。
L1s can be faster, cheaper, and more secure.
L1可以更快,更便宜,更安全。
They aren’t slowed down by a glacially moving L1 data availability stack, or have to compromise security with complex fraud proofs and upgrade multisigs. https://t.co/Ov3YAfz9U4
冰川移动的L1数据可用性堆栈并没有减慢它们的速度,或者不得不使用复杂的欺诈证明和升级Multisigs损害安全性。 https://t.co/ov3yafz9u4
— toly ?? (@aeyakovenko) March 23, 2025
-Toly??(@aeyakovenko)2025年3月23日
Yakovenko added that Solana does not encounter these kinds of problems since it has separate execution and data layers on an efficient base layer.
Yakovenko补充说,Solana不会遇到此类问题,因为它在有效的基础层上具有单独的执行和数据层。
Storage Issues
存储问题
Yakovenko described Solana’s data generation as tiny at 80 terabytes annually, saying that Layer-1 cannot scale because they are hindered by storage.
Yakovenko每年将Solana的数据生成描述为80吨的微小,称第1层无法扩展,因为它们受到存储的阻碍。
“Solana generates a measly amount of data. Like 80TB per year so far. It’s just not enough data to build a business around, but too much for any individual to easily store,” Yakovenko said.
Yakovenko说:“ Solana产生了大量的数据。就像到目前为止每年80TB一样。它的数据不足以建立业务,但对于任何人来说都无法轻松存储。”
The crypto co-founder told users not to create valueless Layer-2 cryptocurrencies, saying earlier this month, “You can skip creating a valueless L2 and just launch a token.”
加密联合创始人告诉用户不要创建毫无价值的第2层加密货币,他本月早些时候说:“您可以跳过创建毫无价值的L2并启动令牌。”
When asked about Solana’s plan on offloading unused storage, he responded that the ledger is going on “filecoin or whatever decentralized storage provider wants it.”
当被问及索拉纳(Solana)卸载未使用存储的计划时,他回答说,分类帐将进行“ Filecoin或任何分散的存储提供商想要的东西”。
Some Do Not Agree
有些不同意
Several crypto investors disagree with Yakovenko, arguing that Layer-2 solutions are necessary.
几位加密投资者不同意Yakovenko,认为第2层解决方案是必要的。
“L1s can’t scale to accommodate 8 billion global users. L2s are needed no matter which chain you see leading the way. And they can be faster, cheaper, more secure, interoperable, specialized to use case, localized or decentralized, evolve fast or ossify,” @RuzhyoX commented on Yakovenko’s post.
“ L1s无法扩展以容纳80亿个全球用户。无论您看到哪条链条,都需要L2S。它们可以更快,更便宜,更安全,更安全,可互操作,专门用于用例,局部化或分散,快速发展或僵化,” @ruzhyox在Yakovenko的帖子上发表了评论。
The Solana co-founder replied that Layer-1 can accommodate 8 billion users, saying, “8 billion * 3 txs per day is sub 300k tps. That fits in under 1gbps of block throughput for 400 byte txs.”
Solana联合创始人回答说,第1层可以容纳80亿用户,说:“ 80亿 * 3 TXS为30万TPS。适合400个字节TXS的1Gbps块吞吐量以下。”
He argued that Solana’s design allows it to compete with every Ethereum (CRYPTO: ETH) Layer-2 solution directly, which is not the case with Ethereum itself. “There is no point to multiple L2s … if a single L2 can handle parallel execution, then it can use up all the blobspace and run every use case.”
他认为,Solana的设计使其可以直接与每个以太坊(Crypto:ETH)第2层解决方案竞争,而以太坊本身并非如此。 “多个L2没有意义……如果单个L2可以处理并行执行,那么它可以用尽所有BlobSpace并运行每个用例。”
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